Math, asked by mamtaraj8112, 1 year ago

The HCF of 36 a⁵b² and 90 a³b⁴ is:
(A) 36 a³b²
(B) 18 a³b⁴
(C) 18 a³b²
(D) 180 a⁵b⁴

Answers

Answered by dishagaur748
0
hey mate!!


here is your answer:

(c) is the correct answer as hcf is the product of smallest power of common factors and here 18a^3b^2 is the smallest power of number .


hope it helped!!
Answered by mysticd
0
Solution :

36a^5b² = 2×2×3×3×a^5b²

90a³b⁴ = 2×3×3×5×a³b⁴

Now ,

HCF( 36a^5b² , 90a³b⁴) = 2 × 3² × a³b²

[ Product of the smallest power of

each common prime factor of the

numbers ]

= 18a³b²

Therefore ,

Option ( C ) is correct.

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