Question

the hcf of 48,84,120 is​

Answer 1

hey mate

find here

the hcf of 48,84,120

so, first do factor its

(1)48=2×2×2×2×3

(2)84=2×2×3×7

(3)120=2×2×2×3×5

take here common factor

so,

hcf of 48,84,120 will be

= 2×2×3

= 12

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Answer 2

Answer:

The HCF of the given numbers is 12.

Step-by-step explanation:

Given: The numbers are 48, 84, and 120.

We have to find the HCF of the above numbers.

• As we know that the greatest common divisor of two or more integers, which are not all zero, is the largest positive integer that divides each of the integers.

We are solving in the following way:

We have,

The numbers are 48, 84, and 120.

First, we will find the factors of the above numbers.

The factors of 48 are: $1, 2, 3, 4, 6, 8, 12, 16, 24, 48$

The factors of 84 are: $1, 2, 3, 4, 6, 7, 12, 14, 21, 28, 42, 84$

The factors of 120 are: $1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 20, 24, 30, 40, 60, 120$

From the above, we can see that 12 is the largest positive integer that divides each of the integers.

Then the greatest common factor is 12.

In this problem, we are assuming we have to find the HCF of the given numbers.

Q. Find the HCF of 48, 84, and 120.