Math, asked by shresthashishir37, 7 hours ago

The HCF of 4p-8 and p^2-4 is

Answers

Answered by bagkakali
0

Answer:

4p-8

=4(p-2)

p^2-4

=(p)^2-(2)^2

=(p+2)(p-2)

so HCF is (p-2)

Answered by hemanthvadapalli123
17

\huge\bold{Question:-}

The HCF of 4p - 8 and p²- 4

\huge\bold{Solution:-}

4p - 8 = 4(p - 2)

 {p}^{2}  - 4 = (p + 2)(p - 2)

HCF is (p - 2)

Used Formulae:-

 {a}^{2}  -  {b}^{2}  = (a + b)(a - b)

Please refer to the attachment

Attachments:
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