Question

The HCF of 5(x³+y³) and 10(x²-y²)is
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Answer 1

Answer:

5(x³+y³)

=5{(x+y)(x²-xy+y²)}

=5(x+y)×5(x²-xy+y²)

10(x²-y²)

=5×2{(x+y)(x-y)}

=5(x+y)×5(x-y)×2(x+y)(x-y)

HCF= 5(x+y)