Math, asked by shaikhjavedshaikhjav, 4 months ago

the hcf of 56 m^4,64 m^3,-40 m^2 n,and 48 m^2 n^2 is.....

Answers

Answered by us051728
3

Answer:

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Answered by msbadrinath3
0

Answer:

HCF=4m^2

Step-by-step explanation:

56m^4= 2×2×7×m×m

64m^3=2×2×2×2×2×2×m×m×m

-40m^2n^2=2×2×2×5×m×m×n×n

Comman factores=2×2×m×m

HCF=4m^2

*If this help you pls make me brainlist*

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