the hcf of 56 m^4,64 m^3,-40 m^2 n,and 48 m^2 n^2 is.....
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Answer:
HCF=4m^2
Step-by-step explanation:
56m^4= 2×2×7×m×m
64m^3=2×2×2×2×2×2×m×m×m
-40m^2n^2=2×2×2×5×m×m×n×n
Comman factores=2×2×m×m
HCF=4m^2
*If this help you pls make me brainlist*
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