Question

the HCF of 615, 984 by short division method​

Answer 1

Hi there!!

I am doing this by Euclids division Lemma.

Look at the attachment

Hope it helps :)

Answer 2

Answer:

123

Step-by-step explanation:

\huge\underline\mathfrak{Question-}Question−

Find the HCF of the following numbers.

615 and 984

\huge\underline\mathfrak{Answer-}Answer−

\large{\boxed{\mathrm{\blue{HCF=123}}}}HCF=123

\huge\underline\mathfrak{Solution-}Solution−

By prime factorisation method,

★ Prime factors of 615 :

\longmapsto⟼ \sf{\boxed{3}}3 × 5 × \sf{\boxed{41}}41

★ Prime factors of 984 :

\longmapsto⟼ 2³ × \sf{\boxed{3}}3 × \sf{\boxed{41}}41

HCF ( Highest common factor ) = 3 × 41

•°• HCF = 123

*for prime factorisation, refer to the attachment*

$$\rule{200}2$$

By using Euclid division lemma,

a = bq + r

984 = (615×1) + 369

615 = (369×1) + 246

369 = (246×1) + 123

246 = (123×2) + 0

HCF = 123

$$\rule{200}2$$

By long division method,

*refer to the attachment*

$$\large{\boxed{\mathrm{\blue{\therefore\:HCF=123