Question

the HCF of 65 and 117 is expressible as 130 + 117 n then the value of n is

Answer 1

Answer:

Let us find the HCF of 65 and 117,

117 = 1 × 65 + 52

65 = 1 × 52 + 13

52 = 4 ×13 + 0

therefore HCF of 65 and 117 is 13.

65m -117 = 13

65m -117 = 13

65m = 117+13 = 130

m =130 / 65 =2

Now, 65 = 5 × 13

117 = 13 × 3 × 3

LCM of 65 and 117 = 5 × 13 × 3 × 3 = 58

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Answer 2

Find the Hcf of 65 and 117

65 =5×13 

117 =3×3×13 

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H.C.F. of 65 and 117 = 13 

according to question 

=>65m -117 = 13 

=>65m = 13+117 

=>65m =130 

=>m =130/65

=>m=2 is your answer.