the hcf of 67and255. pls
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By euclid s Division algorithm a= bq+ r
255= 67× 3+ 54
67= 54× 1+13
54= 13× 4 +2
13= 4× 3+1
4= 3×1+1
3= 1 ×3+0
1 is the hcf of 255 And 67
255= 67× 3+ 54
67= 54× 1+13
54= 13× 4 +2
13= 4× 3+1
4= 3×1+1
3= 1 ×3+0
1 is the hcf of 255 And 67
Answered by
1
Hcf of 67 is 1 and hcf of 255 is 1
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