Question

The HCF of 924, 105 and 525 is. A) 21 B) 84 C) 105 D) 25 Please step by step explanation...

Answer 1

Answer:

21

Step-by-step explanation:

Factor of 924

924 = 2×2×3×7×11

Factor of 105

105 = 3×5×7

Factor of 525

525 = 3×5×5×7

Highest common factor are :-

3×7 = 21

Answer 2

HCF of 924, 105 and 525 is 21

Given :

The numbers 924, 105 and 525

To find :

HCF of 924, 105 and 525 is

A) 21

B) 84

C) 105

D) 25

Solution :

Step 1 of 3 :

Write down the given numbers

The given numbers are 924, 105 and 525

Step 2 of 3 :

Prime factorise the given numbers

924 = 2 × 2 × 3 × 7 × 11

105 = 3 × 5 × 7

525 = 3 × 5 × 5 × 7

Step 3 of 3 :

Find HCF of 924, 105 and 525

We know that for the given two or more numbers HCF is the greatest number that divides each of the numbers

So the required HCF

= HCF of 924, 105 and 525

= 3 × 7

= 21

Hence the correct option is A) 21

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