Question

The HCF of a2 b3 and a3b5 is :-​

Answer 1

Answer:

a²b³= a × a × b×b×b

a³b⁵= a×a×a×b×b×b×b×b

HCF (a²b³ , a³b5)= a²b³

Step-by-step explanation:

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