Question

the hcf of find the greatest 4 digit number which when divided by 18 and 12 leaves remainder 4 in each case​

Answer 1

Answer:

9976 is the greatest 4 digit number which when divided by 18 and 12 leaves the remainder 4.

Step-by-step explanation:

Required number = greater 4 digit number - remainder +4.

N= 18a + 4  

⇒ N-4 = 18a

And N = 12b + 4

⇒ N- 4 = 12 b

Means N is LCM of 18 and 12

LCM (18,12) = 36

N - 4 = 36 m

N = 36m + 4

If n = 277

N = 36 (277) + 4  

= 9972 + 4

= 9976

So, The required number is 9976.