Question

the HCF of of two number is 28 and there LCM is 1449 if number of the number is is 161 find the other​

Answer 1

$\huge \bold \purple{heya \: mate}$

We know that,

HCF×LCM= Product of the two numbers

Here, it is given that

HCF= 28

LCM=1449

One of the numbers=161

Let the other number be 'a'.

Now,

28×1449= 161×a

40572=161a

40572÷161=a

252=a

Therefore,

Answer => 252

Answer 2

HCF×LCM=Product if nos.

=28×1449=(161)x

=28×1449/161=x

=252=x

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