Question

The HCF of of two number is 6 and the lcm is 144 and one number is 36 now find the two number

Answer 1

Answer:

8

Step-by-step explanation:

1.Given,

HCF of the two given numbers = 12

LCM of the two given numbers = 144

The 1st number = 36

Let the 2nd number be x

Now,

Using the formula :

LCM × HCF = product of two given numbers.

144 × 12 = 36 × x

So, the missing number (x) is 48.

2. LCM*HCF=A*B

14*LCM=2352

LCM=2352/14

   =168

3.HCF of two co-primes = 1 .

Given, LCM of them = 156 .

One of them = 13.

Let the other number be x

We know that,

LCM × HCF = products of two numbers.

1 × 156 = 13x .

x = 156/13=12

4.HCF = 75

LCM = 15600

First number = 975

Now,

LCM × HCF = First number × Second number

=> 15600 × 75 = 975 × b

=> b = 15600 × 75 / 975

=> b = 16 × 75

=> b = 1200

4.  8 BECAUSE 8 IS NOT A FACTOR OF 84

PLS MARK BRAINLIEST