Question

The hcf of the algebraic expression 16x2y4 , 20x5y3 ,and 12x3y8z is​

Answer 1

Answer:

Let " f(x) " and " g(x) " be the given polynomials. First, divide f(x) by g(x) to obtain, f(x) = g(x) x q(x) + r (x)

So, deg [ g(x) ] > deg [ r(x) ]. If remainder r (x) = 0, then g(x) is the HCF of given polynomials.

Step 2 :

If the remainder r(x) is not zero, then divide g(x) by r(x) to obtain g(x) = r(x) x q(x) + r₁ (x).

Where r₁ (x) is remainder. If it is zero, then r(x) is the required HCF.

Step 2 :

If it is not zero, then continue the process until we get zero as remainder.

Answer 2

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