Math, asked by kashikaGhosh, 2 months ago

the hcf of the polynomial 10(a-1) (a-2)³,.120(a-3) (a-2)³ and 135(a+3) ( a-2)³ is​

Answers

Answered by richa8ty
3

Answer:

a 3

Step-by-step explanation:

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Answered by harshit5645
6

Answer:

First expression = x2 - 3x - 18

= x2 - 6x + 3x - 18, by splitting the middle term - 3x = - 6x + 3x

= x(x - 6) + 3(x - 6)

= (x - 6) (x + 3)

Second expression = x2 + 5x + 6

= x2 + 3x + 2x + 6, by splitting the middle term 5x = 3x + 2x

= x(x + 3) + 2(x + 3)

= (x + 3) (x + 2)

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