Question

The HCF of the polynomials 12a²b4c2, 18a4b3cand 24a4b3c3 is a) 12a b c b) 6a b c c) 6a bºc? d) 48a%b4cA​

Answer 1

Answer:

Here

12a²b⁴c²=2×2×3×a×a×b×b×b×b×c×c

18a⁴b³c=2×3×3×a×a×a×a×b×b×c

24a⁴b³c³=2×2×2×3×a×a×a×a×b×b×b×b×c×c×c

Now

HCF=2×3×a×a×b×b×b×c

=6a²b³c