The HCF of the two numbers is 6 and their LCM is 144 lf one of the numbers is 36 find the other
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The other number is 24.
Given: The HCF of the two numbers is 6.
The LCM of the two numbers is 144.
One of the numbers is 36
To Find: The other number.
Solution:
- We know that the product of LCM and HCF of any two numbers is equal to the product of the two numbers.
∴ LCM × HCF = n1 × n2 [ where, n1 and n2 are numbers ]
In our question, we have been given,
LCM = 144, HCF = 6, n1 = 36
Thus, putting the respective values in the formula we get,
n2 = ( LCM × HCF ) / n1
⇒ n2 = ( 144 × 6 ) / 36
⇒ n2 = 24
Hence, the other number is 24.
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