The HCF of three equal positive integer s, s, s is -----
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Step-by-step explanation:
we know that the HCF of any three equal positive integers is itself..
so, HCF of s,s,s = s
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answer is : two equal positive integer a=b Step-by-step explanation:
Now,
The Euclid's division algorithm:
a = bq+r; O less than or equal to r < b.
HCF factor of two positive integers a and b, where a>b then a - b >0.
• The HCF of two equal positive integers k, k is a=b=k.
a=b, a - b = 0. were a and b are positive integers.
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