Question

the HCF OF TWO NUMBER IS 11 AND THEIR LCM IS 693 IF ONE OF THE NUMBER IS 77 FIND OTHER​

Answer 1

Answer:

Step-by-step explanation:

Let two numbers be x and y.

Let the factors common to both x and y be a set called a.

Let the factors which are only in x which is not there in y be x1.

Let the factors which are only in y which is not there in x be x2.

Now HCF is variable a itself.

And LCM is a * x1 * x2.

Given, a = 11 .....1

a * x1 * x2 = 693........2

Also a * x1 = 77 .........3

We need to find a * x2 = ?

From equation 2 and 3 we get, x2 = 9 ....4

From 1 and 4 we get , a * x2 = 9 * 11 = 99.

Hope it clears your concept for LCM and HCF.

Answer 2

Answer:

Say 'a' and 'b' are two numbers, so always:

HCF*LCM = a* b

Thus given, HCF = 11, LCM = 693 and one of the numbers (say 'a') is 77,

b = (HCF * LCM) / a

= (11 * 693)/77

= 693/7

= 99

Thus 99 is the answer.