The hcf of two number is 145 and their lcm is 1275 if are number is 725 find the other
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Get the prime factorizations of all three numbers
HCF = 145 = 5*29
LCM = 2175 = 3*5*5*29
one number = 725 = 5*5*29
The other number must contain a factor of 3 for 2175 to be the LCM.
The other number must contain factors 5 and 29 for 145 to be the HCF.
So the other number is 3*5*29 = 435
Hope it helped buddy!!
Please mark as brainliest!! :D
Also, * is multiplication
HCF = 145 = 5*29
LCM = 2175 = 3*5*5*29
one number = 725 = 5*5*29
The other number must contain a factor of 3 for 2175 to be the LCM.
The other number must contain factors 5 and 29 for 145 to be the HCF.
So the other number is 3*5*29 = 435
Hope it helped buddy!!
Please mark as brainliest!! :D
Also, * is multiplication
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