Math, asked by yadavved200, 6 months ago

The HCF of two number is 23 and their LCM is 1449 if one of the number is 161 find the other​

Answers

Answered by Yashicaruthvik
2

Answer:

HCF = 23

LCM = 1449

Let the two numbers be a and b. Let a = 161. We have to find b.

We know that  

HCF(a,b) * LCM(a,b) = a*b

∴23 * 1449 = 161 * b

∴23*1449/161 = b

∴b = 23*9

∴b = 207

Thus, the other number is 207.

second method

Given,

One of the two number is 161.

HCF of two number = 23

LCM of two number = 1449

Let second number = M

HCF × LCM = 161 × M

M = 23 × 1449 / 161

M = 207

Step-by-step explanation:

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Answered by sdpandey1980
2

Answer:

HCF = 23

LCM = 1449

Step-by-step explanation:

Let the two numbers be a and b. Let a = 161. We have to find b.

We know that

HCF(a,b) * LCM(a,b) = a*b

∴23 * 1449 = 161 * b

∴23*1449/161 = b

∴b = 23*9

∴b = 207

Thus, the other number is 207.

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