Question

the HCf of two number is 23 and their LCM is 1449 if one of the numbers is 161 . find the other .

Answer 1

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Given that..,

Hcf = 23

LCM = 1449

One of the number is 161

Let the other number be 'a'

We know that

LCM x HCF = product of two numbers

1449 x 23 = 161 x a

1449 x 23
-------------- = a
161

a = 207


Therefore the other number is 207
________________________


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Answer 2

let other no. =x
LCM*HCF=Product of two numbers
23*1449=161*x
x=23*1449/161=207
Hope it helps you :