The HCF of two number is 23 , and thier LCM is 1449. If one of them is 207 , find the other
Answers
Answered by
0
Answer:
Given, HCF=23
LCM=1449
Let the two numbers be a and b. Let a=161. We have to find b.
We know that
HCF(a,b)×LCM(a,b)=a×b
⇒23×1449=161×b
⇒23×
161
1449
=b
⇒b=23×9
∴b=207
Thus, the other number is 207.
Using this method you can solve you question
Answered by
0
Answer:
Here's your answer.
Step-by-step explanation:
Let the other number be b and HCF = a,b LCM = a x b
Therefore 23 x 1449 = 207 x B
33327 = 207 x b
b = 33327/207
b= 161 Therefore The other number is 161.
PLEASE MARK ME AS THE BRAINLIEST.
Similar questions