Question

the hcf of two number is 4 and the two other factors of LCM are 5 and 7 find the smaller of two numbers ​

Answer 1

Answer:

20

Step-by-step explanation:

Given the hcf of two number is 4 and the two other factors of LCM are 5 and 7 find the smaller of two numbers ​

Let the numbers be a and b, where a and b are co prime to each other.

Now given LCM = 4 a b

So we have 4 a b = 4 x 5 x 7

So a = 5 and b = 7

We get two numbers as 4 x 5 and 4 x 7 which will be 20 and 28.

Now the smallest number will be 4 x a = 4 x 5 = 20

So the smallest among two numbers will be 20

Answer 2

The smaller number is 20.

Step-by-step explanation:  Given that the H.C.F. of two numbers is 4 and the other two factors of the L.C.M are 5 and 7.

We are to find the smaller of the two numbers.

Let a and b be the two numbers where a < b.

Since the L.C.M. has three factors 4, 5 and 7 and H.C.F. of a and b is 4.

So, 4 is a factor of both the numbers a and b.

Also, 5 is a factor of one number and 7 is a factor of a=4×5=20,b=4×7=28.

Thus, the two numbers are 20 and 28., and so the smaller number is 20.