Question

the HCF of two number is 5,their LCM is 60 one of the number is 15,find the other no ​

Answer 1

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GIVEN :

HCF = 5, LCM = 60 and One number is 15.

FIND :

We have to find the other number.

SOLUTION :

• Let other number be M.

We know that..

Product of two numbers=LCM×HCF

Product of two zeros = One number × Other number.

So,

One number × Other number = LCM × HCF _______ (eq 1)

Put the known values in (eq 1)

=> 15 × M = 60 × 5

=> 15M = 300

=> M = 20

_____________________________

M=20

(Other number)

___________ [ ANSWER ]

_____________________________

☆ VERIFICATION :

From above calculations we have M = 20

Put value of M in (eq 1)

=> 15 × 20 = 60 × 5

=> 300 = 300

L.H.S. = R.H.S.

Answer 2

Answer:

20

Step-by-step explanation:

given

HCF = 5

LCF = 60

One Number a = 15

Another number b = ( HCF × LCF ) / a

= (5× 60) / 15 = 20