Question

The HCF of two number is 56 and their LCM each 2352 if one of the number is 196 find the other number

Answer 1

Answer:

672

Note:

• Product of two numbers ( not both of which are zero) is equal to the product of their HCF and LCM . ie ; a × b = HCF(a,b) × LCM(a,b) .

Solution:

Let the required number be n.

1st no. = 196

2nd no. = n

HCF = 56

LCM = 2352

Now,

We know that ;

=> 1st no. × 2nd no. = HCF × LCM

=> 196n = 56 × 2352

=> n = 56 × 2352 / 196

=> n = 672

Hence,

The required number is 672 .