the HCF of two number is 847 and1650 is 11.find their LCM
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3
Answer:
61
Step-by-step explanation:
Let the divisor be y
dividend =divisor×quotient+remainder
1679 =y×27+32
1679-32= 27y
1647 = 27y
y = 1647/27
y = 61
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