Question

The HCF of two number is one sixth of the LCM of those number. I If one of the number is 15, Find the other?

Answer 1

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Let us take the two numbers as h.a and h.b, where 'h' is the HCF.

Then the LCM would be h.a.b

In the given question, h.a.b = 6h

Or, a.b = 6

There are two distributions of 6 over two numbers, 2*3 or 1*6

The numbers would then be 2h & 3h or h & 6h

If one of the numbers is 15, the first case 2h can't be 15, 3h must be 15, thus the other number would be 2h=10

The second case 6h can't be 15, h has to be 15, thus 6h would be 90

thus, there are two possibilities for the 2nd number: 10 or 90

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