Math, asked by Nishchitnish9876, 11 months ago

The hcf of two numbers 12906 and 14818 is 478. The lcm is

Answers

Answered by DaIncredible
24

Answer:

L.C.M = 400086

Step-by-step explanation:

We know that L.C.M (a, b) × H.C.F (a, b) = a × b

Putting the given values we get:

L.C.M × 478 = 12906 × 14818

=  \frac{12906 \times 14818}{478}  \\  \\  = 27 \times 14818 \\  \\   \bf= 400086

Answered by Anonymous
36

HCF = 478

Two numbers are : 12906 and 14818

_________ [GIVEN]

• We have to find the LCM.

______________________________

Solution:

We know that

Product of two numbers = LCM × HCF

=> 12906 × 14818 = LCM × 478

=> 191241108 = LCM × 478

=> LCM = \dfrac{191241108}{478}

=> LCM = 400086

______________________________

\textbf{LCM = 400086}

__________ [ANSWER]

______________________________

✡ Product of two numbers = LCM × HCF

=> 12906 × 14818 = 40086 × 478

=> 191241108 = 191241108

__________ [HENCE VERIFIED]

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