Question

The HCF of two numbers is 13 and their LCM is 273. How many such pairs of numbers are possible.(a) 1. (b)2. (c)3. (d)none of these​

Answer 1

Answer:

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Answer 2

Answer:

HCF is 13 .

Means there is definitely one 13 in the LCM

Let's take it out,and see what except 13 is in LCM.

Then we will get, 27313=21

Means there is 21 in LCM.

As we know 21=7×3

But HCF is 13 of the two numbers.

So,two numbers are 13×3=39 & 13×7=91.

Sum will be 39+91=130.

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