The HCF of two numbers is 145 and their
LCM is 2175. If one of those numbers is
725, find the other number
Answers
Answered by
2
Answer:
HCF×HCF=A×B
145×2175=725B
B=145×3= 435
Answered by
5
Answer:
two numbers a and b is
Product of two numbers = HCF × LCM
____________________________
According to the given problem
HCF = 145 ,
LCM = 2175,
One number = a = 725
Let the second number = b
a × b = HCF × LCF
b = ( HCF × LCM ) / a
b = ( 145 × 2175 )/ 725
b = ( 145 × 3 × 725 )/ 725
After cancellation ,
b = 145 × 3
b = 435
Therefore ,
Second number = b = 435.
hope it helps you mate.
please thank and mark my answer as brainliest.
@ ANUSHA ❤✌
Similar questions