The HCF of two numbers is 145 and their lcm is 2175 .If one numbers is 435 find the other number
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__________________________
Relation between HCF and LCM of
two numbers a and b is
Product of two numbers = HCF × LCM
____________________________
According to the given problem
HCF = 145 ,
LCM = 2175,
One number = a = 725
Let the second number = b
a × b = HCF × LCF
b = ( HCF × LCM ) / a
b = ( 145 × 2175 )/ 725
b = ( 145 × 3 × 725 )/ 725
After cancellation ,
b = 145 × 3
b = 435
Therefore ,
Second number = b = 435
____________________________________
Relation between HCF and LCM of
two numbers a and b is
Product of two numbers = HCF × LCM
____________________________
According to the given problem
HCF = 145 ,
LCM = 2175,
One number = a = 725
Let the second number = b
a × b = HCF × LCF
b = ( HCF × LCM ) / a
b = ( 145 × 2175 )/ 725
b = ( 145 × 3 × 725 )/ 725
After cancellation ,
b = 145 × 3
b = 435
Therefore ,
Second number = b = 435
____________________________________
Answered by
3
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