Math, asked by ganesh846869, 9 months ago

the HCF of two numbers is 15 and their LCM is 315. If one of the numbers is 45 find the other​

Answers

Answered by agnus04
6

Answer:

105

Step-by-step explanation:

HCF*LCM=a*b

let a be 45 and b be the number

15*315=45*b

4725=45*b

4725÷45=b

105=b

Answered by Anonymous
13

Answer :-

The other number is 105.

Solution :-

Given

HCF of two numbers = 15

LCM of two numbers = 315

One of the number= 45

Let the other number be x

We know that

Product of two numbers = LCM * HCF

⇒ 45 * x = 315 * 15

⇒ 45x = 4725

⇒ x = 4725/45

⇒ x = 105

Therefore the other number is 105.

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