the HCF of two numbers is 15 and their LCM is 315. If one of the numbers is 45 find the other
Answers
Answered by
6
Answer:
105
Step-by-step explanation:
HCF*LCM=a*b
let a be 45 and b be the number
15*315=45*b
4725=45*b
4725÷45=b
105=b
Answered by
13
Answer :-
The other number is 105.
Solution :-
Given
HCF of two numbers = 15
LCM of two numbers = 315
One of the number= 45
Let the other number be x
We know that
Product of two numbers = LCM * HCF
⇒ 45 * x = 315 * 15
⇒ 45x = 4725
⇒ x = 4725/45
⇒ x = 105
Therefore the other number is 105.
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