Question

the HCF of two numbers is 16 and their LCM is 160 .if one of the numbers is 32,then find the other number

Answer 1

Answer:

$\bf \pink{\: let \: the \: no. \: be \: x \:} \\ \bf \: hcf = 16 \: \: \: \: lcm = 160 \\ \bf given \: \: no. = 32 \\ \\ \bf \pink{ \: acc. \: to \: que : - }\\ \bf \: product \: of \: hcf \: and \: lcm = product \:of \: two \: no.s \\ \bf16 \times 160 = 32 \times x \\ \bf= > 32 \times x = 16 \times 160 \\ \bf \: 32x =16 \times 160 \\ \bf x = \frac{160 \times 16}{32} \\ \bf x = 80$

hope it helps you dear....

Answer 2

Answer:

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Step-by-step explanation:

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