The HCF of two numbers is 18 and their LCM is 630. if one of the numbers is 36,then the other number is
Answers
the other number is 315
given, HCF of two numbers is 18 and their LCM is 630. one of the numbers is 36 then we have to find the other number.
using formula,
HCF of {a b} × LCM of {a, b} = a × b
let the other number is b,
HCF of {36, b} = 18 and LCM of {36, b} = 630
so, 18 × 630 = 36 × b
⇒b = 315
[ note : if HCF of two numbers is m and LCM of these two numbers is n, then we can suppose that two numbers are ma, mb where a and b are co-prime number.
now, LCM of ma and mb , n = mab
so, product of LCM and HCF = mab × m = m²ab
and product of numbers = m²ab
that's why, product of LCM and HCF = product of numbers ]
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Answer:
315
Step-by-step explanation:
H.C.F = 18
L . C . M = 630
One number = 630
Other number = ?
Since we know the property of H . C . F & L . C . M
The product of L .C .M and H .C . F of any two given natural number is equal to their products.
18 * 630 = 36 * (other number)
other number = 315