The hcf of two numbers is 2 and their lcm is 154. If the difference between the number is 8, then the sum is
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remaining factorization u do
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vidisha30:
You answered the question really well...
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HCF=2
LCM=154
Let the numbers be a and b
a-b=8
a=8+b
We know that,
HCF×LCM=a×b
2×154=(8+b)×(b)
308=8b+b square
b square+8b-308=0
b square+22b-14b-308=0
b(b+22)-14(b+22)=0
(b+22)(b-14)=0
b=-22,14
Let us take a positive number which is 14
So,b=14
a=8+b
a=8+14
a=22
Sum=a+b=22+14=36
LCM=154
Let the numbers be a and b
a-b=8
a=8+b
We know that,
HCF×LCM=a×b
2×154=(8+b)×(b)
308=8b+b square
b square+8b-308=0
b square+22b-14b-308=0
b(b+22)-14(b+22)=0
(b+22)(b-14)=0
b=-22,14
Let us take a positive number which is 14
So,b=14
a=8+b
a=8+14
a=22
Sum=a+b=22+14=36
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