the HCF of two numbers is 21 and their LCM is 3003. if one of the number is 231, find the other number
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нεүα мαтε
Let the other number be x
We know,
HCF × LCM = PRODUCT OF THE NUMBERS
=> 21 × 3003 = 231 × x
Let the other number be x
We know,
HCF × LCM = PRODUCT OF THE NUMBERS
=> 21 × 3003 = 231 × x
creamiepie:
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