the HCF of two numbers is 23 and their LCM is 1449. If one of the numbers is 161, find the other.
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Answered by
11
We know that LCM × HCF = product of numbers
Let the other number be x
So, 161 × x = 23 × 1449
=> x = 207
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Answered by
5
let a be 161 and b be the other number.
thus hcf x lcm =a x b
23x1449 = 161 . b
thus b=7
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