Question

The hcf of two numbers is 23 and then lcm is 1449, if one of the number is 207 then find the other.

Answer 1

$\huge\fbox\red{Answer=161}$

let the two no. be a and b.

Given:

HCF =23 and LCM =1449

We know that:-

a×b=hcf×lcm

207×b=23×1449

$b = \frac{23 \times 1449}{207 } \\ = \frac{33327}{207} \\ \\ = 161.$

So the answer is 161

For checking:-

if we find the HCF of 207 and 161=23

if we find the LCM of 207 and 161=1449

so our answer is correct.

Answer 2

$\sf{\huge{\underline{\green{Given :-}}}}$

• The hcf of two numbers is 23 and then lcm is 1449, One of the number is 207 .

$\sf{\huge{\underline{\green{To\:Find :-}}}}$

• The other number.

$\sf{\huge{\underline{\green{Answer :-}}}}$

According to the question ,

• The hcf of two numbers is 23 .

• The lcm is 1449 .

• One of the number is 207.

Let the other numbers be x .

One of the number is 207.

We have to find the value of x .

We know that,

H.C.F × L.C.M. = a × b

➝ 23 × 1449 = 207 × b

➝ 33327 = 207 × b

➝ 33327/207 = b

➝ 161 = b

The other number is 161 .