The hcf of two numbers is 27 and their lcm is 162 . If one of the number is 54 ,find the other?
Answers
Answered by
299
Hello friend
One number is 54
So let the other number be y
We know that the product of two numbers will be equal to the product of their LCM and hcf.
54×y=27×162
y=27×162/54
y=162/2
y=81
The other number is 81
Hope it helps!
One number is 54
So let the other number be y
We know that the product of two numbers will be equal to the product of their LCM and hcf.
54×y=27×162
y=27×162/54
y=162/2
y=81
The other number is 81
Hope it helps!
Answered by
167
HI !
HCF = 27
LCM = 162
One no: = 54
Unknown no: = x
we know that ,
HCF x LCM = product of two no:s
27 x 162 = 54x
4374 = 54x
x = 4374/54
= 81
∴ The other no: is 81
HCF = 27
LCM = 162
One no: = 54
Unknown no: = x
we know that ,
HCF x LCM = product of two no:s
27 x 162 = 54x
4374 = 54x
x = 4374/54
= 81
∴ The other no: is 81
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