Question

The hcf of two numbers is 27and their lcm is 62.if one of the numbers is 1 find the other number

Answer 1

Answer:

we know that the product of HCF and LCM is equal to the product of the two numbers .

So 27×62=1×other number

therefore other number is 27×62/1.

Answer 2

Given Question :-

The hcf of two numbers is 27and their lcm is 62.if one of the numbers is 1 find the other number.

To find :-

The other number =?

Solution :-

Let the other number be x.

As we know that H.C.F×L.C.M=product of the two numbers.

Therefore according to the question,

H.C.F×L.CM=1×x

27×62= 1× x

x = 1674

So the required number is 1,674.

___________________________________

$Be \: brainly$