Question

The HCF of two numbers is 27and their LCM is162. If one of the number is 54, what is the other number?​

Answer 1

Given

$\bold{HCF \ of \ the \ two \ numbers} = 27$

$\bold{LCM \ of \ the \ two \ numbers} = 162$

$\bold{One \ of \ the \ numbers} = 54$

Let the other number be x.

SOMETHING YOU NEED TO KNOW

$\boxed{\bold{Product \ of \ 2 \ numbers} = HCF \times LCM}}}$

$\implies 54x=162 \times 27$

$\implies x = \dfrac{162 \times 27 }{54}$

$\implies x= 81$

$\boxed{\boxed{\bold{Therefore, \ the \ other \ number \ is \ 81}}}}$

                                                                         

Answer 2

HCF of the two numbers = 27

LCM of two numbers = 162

One of the number = 54

Let the other number be $x$

Product of two numbers = HCF × LCM

$\bold\orange{54x = 162 \times 27}$

$\bold\orange{x = \frac{162 \times 27}{54}}$

$\bold\orange{x = 81}$

Therefore the other number is 81