Question

The HCF of two numbers is 3 and their LCM is 54. If one of the number is 27 , find the other number.

Answer 1

Answer:

6

Step-by-step explanation:

two numbers a and b, we know that

(a×b)=HCFof(a,b)×LCMof(a,b)

Here,

a=27 ,HCF=3 ,LCM=54

Therefore,

(27 ×b)=(3 × 54)

b= (3×54) / 27

b= 6

Hence, the other number is 6 .

Answer 2

Given :-

• The HCF of two numbers is 3 and their LCM is 54. If one of the number is 27

To find :-

• Other number

Solution :-

• HCF of two numbers = 3

• LCM of two numbers = 54

• One of the number = 27

As we know that

→ LCM × HCF = Product of two numbers

→ LCM × HCF = a × b

Where " a " is first number and " b " is second number.

According to the given condition

→ LCM × HCF = a × b

→ 54 × 3 = 27 × b

→ 162 = 27b

→ b = 162/27

→ b = 6

Therefore,

• Other number is 6

Verification :-

• LCM × HCF = Product of two numbers

→ 54 × 3 = 27 × 6

→ 162 = 162

• Hence verified