Question

The hcf of two numbers is 4 and the two other factors of lcm are 5 and 7. Find the smaller of the two numbers.

Answer 1

Answer:

Step-by-step explanation:

Given the hcf of two number is 4 and the two other factors of LCM are 5 and 7 find the smaller of two numbers ​

Let the numbers be a and b, where a and b are co prime to each other.

Now given LCM = 4 a b

So we have 4 a b = 4 x 5 x 7

So a = 5 and b = 7

We get two numbers as 4 x 5 and 4 x 7 which will be 20 and 28.

Now the smallest number will be 4 x a = 4 x 5 = 20

Hope it helps you...