The HCF of two numbers is 4 and the two other
factors of LCM are 5 and 7. Find the smaller of the
two numbers.
a) 10 6) 14 c) 20 d) 28
Answers
The smaller number is 20.
Step-by-step explanation: Given that the H.C.F. of two numbers is 4 and the other two factors of the L.C.M are 5 and 7.
We are to find the smaller of the two numbers.
Let a and b be the two numbers where a < b.
Since the L.C.M. has three factors 4, 5 and 7 and H.C.F. of a and b is 4.
So, 4 is a factor of both the numbers a and b.
Also, 5 is a factor of one number and 7 is a factor of the other number.
Therefore, we must have
\begin{lgathered}a=4\times5=20,\\\\b=4\times7=28.\end{lgathered }a=4×5=20,b=4×7=28.
Thus, the two numbers are 20 and 28., and so the smaller number is 20.
Answer:
HEY BUDDY...
GOOD EVE...♥
HCF x LCM = PRODUCT OF 2 NOS..
4 x 35 = 140
SO THE TWO NUMBERS MUST BE 10 AND 14...
ACCORDING TO THE OPTION YPU HAVE GIVEN...
SO 10 IS THE SMALLEST NUMBER...
HOPE IT HELPS...!!!
HVE A GRT DAY AHEAD...^_^