Question

the HCF of two numbers is 5 and LCM is 150. If one no. is 25 find the other​

Answer 1

Answer:

If 150 is a multiple, then all of the factors of the second number must also be factors of 150 which are: 5 (twice), 2 and 3.

Since 150 is the LCM, all of those factors must be either in our number or 25. Since 25 has just 5 (twice) as a factor, both 2 and 3 must be factors.

The remaining question is how many 5s we have. Since the GCF with 25 is 5, our number must exactly one 5.

So the factors of our number are: 2, 3, and 5. There is one number with exactly these factors = 2*3*5 = 30.

Answer 2

Answer:

We know that

HCF * LCM = Product of two integers

5 * 150  = 25 * x

750 = 25x

x=75 / 25

x = 30

the other number is 30