The HCF of two numbers is 6 and their LCM is 36 if one
of the number is 12, find the others
Answers
Answered by
2
Answer:
HCF × LCM= a×b
HCF=6
LCM=36
a=12
b=?
6×36=12×b
18=b
Answered by
2
Step-by-step explanation:
we have formula
LCM*HCF=PRODUCTS OF NUMBERS
6*36=12*SECOND NO
216=12*SECOND NO
SECOND no=216/12
2nd no=18
since the second no. is 18
hope this helps you
Similar questions