Math, asked by dasdarshil0, 8 months ago


The HCF of two numbers is 6 and their LCM is 36. If one of the numbers is 12, find the
other?

Answers

Answered by amitkumar44481
69

AnsWer :

18.

To FinD :

The other number?

SolutioN :

  • Let the other number be x.

A / Q,

We know that,

 \tt \dagger \:  \:  \:  \:  \: HCF  \times LCM = Product \:  of  \: two  \: number.

So,

  • HCF is 6.
  • LCM is 36.
  • One number is 12.
  • Other number be x ( Let above )

 \tt \longmapsto \:  \:  \:  \:  \: 6  \times 36 = 12x.

 \tt \longmapsto \:  \:  \:  \:  \: 216 = 12x.

 \tt \longmapsto \:  \:  \:  \:  \: x =  \dfrac{\cancel{216}}{\cancel{12}}

 \tt \longmapsto \:  \:  \:  \:  \: x = 18.

Therefore, the value of other number is 18.

\rule{200}3

MorE InformatioN :

 \tt \ \bigstar \:  \:  \:  \:  \: HCF  \times LCM = Product \:  of  \: two  \: number.

Answered by BrainlyShadow01
73

Answer:

Question:-

The HCF of two numbers is 6 and their LCM is 36. If one of the numbers is 12, find the other?

Answer:-

Given,

HCF of two numbers is 6

LCM is 36

one of the numbers is 12

Then,

6 × 36 = 12x

6 × 36 = x. [ 6/12 = 1/2]

12

36 = x

2

18 = x

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