Math, asked by kumaraswamyandabatla, 1 month ago

the hcf of two numbers is 6 and thier lcm is 36. lf one of yhe numbers is 12 find the other
plz tell anwer anyone who will tell i will give them 1 thing you want that tell the answer​

Answers

Answered by JoylynJohn
2

Answer:

hcf(a,b)× lcm(a,b) = a×b

hcf = 6

lcm = 36

a = 12

6 × 36 = 12× b

6× 36 / 12 = b

b = 18

Answered by tennetiraj86
0

Step-by-step explanation:

Given:-

The hcf of two numbers is 6 and thier lcm is 36.

One of the numbers is 12 .

To find:-

Find the other number?

Solution:-

Given that

The HCF of two numbers = 6

The LCM of two numbers = 36

One of the two numbers = a = 12

Let the other number be b

Now, We Know that

LCM × HCF = product of the two numbers

=> LCM × HCF = ab

On Substituting these values in the above formula

=> 36×6 = 12×b

=> 12×b = 36×6

=> 12 b = 216

=> b = 216/12

=> b = 18

The other number = 18

Answer:-

The other number for the given problem is 18

Used formula:-

  • LCM × HCF = product of the two numbers
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