the hcf of two numbers is 6 and thier lcm is 36. lf one of yhe numbers is 12 find the other
plz tell anwer anyone who will tell i will give them 1 thing you want that tell the answer
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Answer:
hcf(a,b)× lcm(a,b) = a×b
hcf = 6
lcm = 36
a = 12
6 × 36 = 12× b
6× 36 / 12 = b
b = 18
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Step-by-step explanation:
Given:-
The hcf of two numbers is 6 and thier lcm is 36.
One of the numbers is 12 .
To find:-
Find the other number?
Solution:-
Given that
The HCF of two numbers = 6
The LCM of two numbers = 36
One of the two numbers = a = 12
Let the other number be b
Now, We Know that
LCM × HCF = product of the two numbers
=> LCM × HCF = ab
On Substituting these values in the above formula
=> 36×6 = 12×b
=> 12×b = 36×6
=> 12 b = 216
=> b = 216/12
=> b = 18
The other number = 18
Answer:-
The other number for the given problem is 18
Used formula:-
- LCM × HCF = product of the two numbers
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