Question

The HCF of two numbers is 61 while their sum is 1159. How many pairs of such numbers are possible? Enter​

Answer 1

sorry I don't know answer but I need points

Answer 2

Solution :-

Let us assume that, the two numbers are 61x and 61y .

So,

→ 61x + 61y = 1159

→ 61(x + y) = 1159

→ x + y = 19 .

checking numbers now we get,

• At x = 1 , y = 18
• At x = 2, y = 17
• At x = 3, y = 16
• At x = 4, y = 15
• At x = 5, y = 14
• At x = 6, y = 13
• At x = 7, y = 12
• At x = 8, y = 11
• At x = 9, y = 10

therefore,

→ Total possible pairs are = 9 + 9 = 18 (Ans.)

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